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Keystones, Windows and More About Arches
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| What
is a keystone? A keystone is the stone at the top of an arch. Here is
an arch seen from the viewpoint of a rather self-important keystone.
One thing is sure, the keystone is not in the position of maximum stress. But do we need a keystone at all? What can we deduce without getting out our finite element analysis program, or using the calculus of variations? Yes, we should always try to use the simplest means to discover answers, though it is a good idea to use at least two methods of obtaining an answer. Don't forget - if you calculate something twice, using the same initial assumptions, and you get two different answers, at least one of them must be wrong, and both may be wrong. The same is true for measurements. Even if two different results agree, they are not thereby proved correct. To be more accurate, the results should not differ by an amount which is incompatible with the accuracy of your method of working. Let's ask a question about the stress in the keystone. In which direction does it operate? Imagine a vertical line through the middle of the arch. By symmetry, the forces in the two halves must be mirror images. In the keystone, if the forces had a vertical component at the centre line, then these would not cancel out, though the horizontal forces would. Therefore the stone would move, in translation or in rotation, until the vertical force vanished or the arch collapsed, and in particular, no shear would remain. So the forces along the centre line must be horizontal. So if we cut the keystone in two halves down its middle, no sliding would occur, because no shear stress is present. Now we don't have a keystone - we have two equal partners at the top. So an arch can work perfectly well with an even number of voussoirs, and no keystone. Since this page is rather negative about keystones, we could also mention an article in Arab Construction World Nov 2005 / Vol XXII - Issue 7, in which Hakan Sandbirg points out that the value of the keystone is that it reminds us that "until the structure is complete, we have to keep thinking" - an important point. You will have noticed that we have stated, without proof, that the stresses are least at the top and greatest at the bottom. Can you prove this without doing any mathematics?
Keystones are not needed. So we don't need a page about keystones. Ah well, let's just fill up this page with miscellaneous observations about beams and arches. Actually, you will probably have already realised from the existence of three-pin arches that the keystone is inessential.
By the way, the arch in the diagram at the top of the page will not stand unless the lowest voussoirs are provided with inward forces to stop them spreading, unless the mortar (and the blocks) are very resistant to shear and bending. Can you see why? What do clocks, lamps and mirrors and dinner plates have in common? An invitation to designers to produce not only work of distinction, but work with just about every other characteristic, not always tasteful, as you can see in shops and advertisements. You can even buy plates and mirrors that are clocks. Architecture is a much more restrained discipline, if only because you have to build something that stands up for a reasonable time. Even the architecture of dictators and totalitarian states usually errs in the direction of big, empty, and pretentious, rather than over ornate, at least on the outside. The pyramids of Giza are extreme examples. If large structures are dominated by the laws of physics, what about small details, such as windows?
The picture at left has been exaggerated vertically to show the angular change in the left hand block, which has cracked, and the slippage of the right hand block, resulting in the cracks at the top right hand of the picture.
The pictures below show openings in buildings, arranged roughly in order of the ratio of rise to span. Can you classify each one as either arch or beam?
Voussoirs Voussoirs are the wedge-shaped blocks that make up a masonry arch. But are they actually acting as wedges? Look at the diagram below, showing how a wedge is used to raise a heavy object, or perhaps to stop a door moving sideways. The red arrows represent the main forces acting on the wedge. They are not equal and opposite. In the absence of any other forces, they would force the wedge out of the gap. But there are, in fact, two other forces, shown by the small yellow arrows. These are the forces of friction. The angle of the wedge in radians must be less than the coefficient of friction, that so-called constant which is so popular with the authors of elementary physics books. As voussoirs are wedge-shaped, we might wonder whether they might act as wedges. The answer, it turns out, is no, not if the arch is funicular. The page about funiculars shows how a non-funicular arch requires internal forces to resist shears and bending moments. These may be taken to correspond loosely to the friction in the wedge. The distinction made here between wedges and voussoirs is probably not completely clear-cut. An essential difference is that a wedge is usually a small object that is used to separate two large objects, whereas a voussoir is surrounded by other voussoirs of similar size. We seldom have to consider the weight of a wedge, whereas that of a voussoir is highly significant. Let us consider a fragment from a semicircular arch, because it is easy to draw. And if a semicircular arch was good enough for the Romans, it will be good enough for us. There is a fundamental difference between the voussoir and the wedge. The weight of the voussoir is the force that turns the line of thrust through the arch: no friction is needed in order to balance the parts. If you were to replace the marked block by a much lighter one, then in the absence of any friction, it would be squeezed out like a frictionless wedge, or at least the arch might be distorted in some other way. And if the one voussoir were very heavy, and the rest of the arch very light, that one voussoir could slide inward. The next question is this - Is the position as built, the most stable? If you were to displace one or more blocks radially, inwards or outwards, would the total energy go up, go down, or stay the same? If you think about a hanging chain or cable, any disturbance raises the energy. Presumably any disturbance of the inverted case, an arch, lowers the energy. So the arch is not inherently stable, unless it is given rigidity by virtue of its thickness. Do you think that the minimum thickness for a stable arch is related to the criteria for a stable strut, such as the Euler criterion? |
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