Indeterminacy

  

24th August 2001     Back to Bridges    back to Home page

Suppose you think that a structure is too weak.  One solution is to add more parts at the presumed weak place.  What is the purpose of the gussets in the objects shown below?

 

The left hand diagram above shows a tube welded to a flange.  We might decide that the attachment is too weak, and so we might weld four brackets to the tube and flange, as in the right hand diagram.  What could be wrong with that?

If the system were indeed already over-stressed, we may have made it worse.  We might have done the welding badly, so that thermal stresses were not allowed to anneal out.  We might have shaped the triangles badly, and forced a distortion when adding them.

These new stresses might nullify completely any possible gain from the new parts.  In effect, we may have made the system weaker.

If there is a cyclic stress, from pressure or temperature, the newly added stresses may cause failure by fatigue to happen  earlier than it would have without the modifications. 

The diagrammatic example is not very realistic, as the tube is thin and the gussets are thick.

For another example, imagine that four people have been asked to work together to hold a heavy object.  If they all have different ideas about where the object should be, they will waste force in opposing each other, and they may distort the object if it is not very rigid.  The photographer’s tripod illustrates a similar point.

 

When we see an apparently complicated network of struts, can we work out why each one is there, and why no others are there?  Two different questions can be asked.  Firstly, what is the simplest arrangement that will make the construction rigid?  Secondly, which members are in tension and which in compression?

Looking at the second question, we could ask, thirdly, does each member remain always in tension or always in compression as a live load moves across the bridge?

Let’s see if we can answer these questions.

If we want to find out which members are in tension and which in compression, we can often get somewhere by imagining them made of something like stiff rubber, that can change visibly when stressed.  A member in tension will tend to stretch.  A member in compression will tend to shrink.

Or we can imagine a normal rigid bridge, and then imagine removing one member.  By working out what would happen we can see whether the member was in tension or in compression.

This has been done in two of the diagrams below.  What can you tell about the missing members?

In  the third diagram above, is the missing piece needed at all?  Think of two cases.  In the first case, the truss is hinged at both supports.  In the second case, it is hinged at the left side, but only rests on the right, so that it can slide along when it expands or contracts because of temperature changes.

Now what do you think?  In the first case, what does removing the member do to the forces at the supports?  

Answers at bottom of page.

 

Sabrina5.jpg (32439 bytes)The deck of the Sabrina bridge at Worcester is built in sections, so that the triangles formed by these and the cables are independent.  Therefore any change in the length of one cable has minimal effects on the others.

An example of an over-determined structure would be a pair of cantilevers joined together without the usual suspended span.  If the ends do not match, one will be pulled up and one will be pulled down.  If nobody records the shift and calculates the result, the stresses in each half are unknown, though the average of the two halves would be as per the design.

The next set of diagrams show simple frameworks and the effects of adding extra struts.  The diagram at top right is only there to provide a labelling scheme for the joints.

 

 

In the top two diagrams there are only enough parts to make the system rigid.  This rigidity does not rely on any stiffness at the joints, as long as the bolts fit the holes.  But in the bottom left diagram the extra strut BC has been added.  What effect does it have?

If all the parts were perfectly made, the whole thing would fit well without problems.  But nothing can be perfect.  There must be variations in manufacture, however small.  There are two simple cases.  

Firstly, the slackness of the bolts in the holes exceeds the tolerances in the distances between the holes in each strut.  In such a case the framework can be loosely assembled and then the bolts can be tightened.

Secondly, the bolts fit the holes better than the tolerance in length.  In this case, adding the sixth strut BC could be impossible without some changes to the lengths.  In other words, the struts are strained.  Once the framework has been assembled, it will end up in a configuration of minimum energy.

There are two conditions for a cross-braced quadrilateral.  Either both diagonals are too short, or both are too long.

The strain energy in each strut is equal to the square of the strain, multiplied by a constant which is particular to each bar.  For identical bars, the constant will be the same.  So minimum energy is related to the sum of weighted squares of the strains.

If the parts of a structure are so thick that the forces may not be purely longitudinal, it may be impossible to know the internal stresses.  This can arise if the treatment has set up residual stresses, as in the case of a block of hot glass that is suddenly cooled.

Why does any of this matter?  It matters because the relationship between stress and strain in most structural materials is such that quite small strains can result in stresses which are comparable with the maximum safe stress.

Let’s try a simple example.  Suppose that a sample of steel has a Young’s modulus of 200 GN per m2, and it has a tensile strength of 400 MN per m2.  The first quantity gives the ratio of stress to strain, and the second gives the stress at breaking point.  Suppose we try to fit the part into a place that is 0.1 % too long, that is, one part in a thousand, which does not look like much.  The strain is therefore 0.001, and so the stress is 0.001 X 200 GN per m2, which is 200 MN per m2, one half the tensile strength.  So we have created a big stress in the part, even before loading the structure.

Thermal expansion is often large enough to threaten structures.  It is for this reason that railways need gaps between the sections of rail, unless the rails are held firmly in place.  Bridges, too, may need provision for expansion.  A beam may be fixed at one end, and on rollers at other supports.  Curved structures such as suspension cables and arches can deflect, relieving the stress, but the flat deck may still need preventative measures.

In an over-determined structure, what happens if you remove an old or damaged member?  If it was carrying some forces, all the other members will adjust when it is removed, as when one segment of a spider-web is cut.  When a new part is put in, will the stresses return to their original state?  Not if the new part is made to fit the new situation.  Successive replacements might produce a random walk of stress variations in a structure.  But will the changes really be random?  Might they not systematically move in one direction?  Or might they move until certain members consistently had no further effect?

Most structural materials do not allow inspection of the interior to measure the stresses and strains, except possibly by methods such as neutron diffraction.  Strain of the surfaces can be measured using strain gauges, which are small devices which change their electrical properties such as resistance, when strained.

Using a transparent model, it is sometimes possible to evaluate the average strain along a line by using polarised light.  If the molecules are asymmetrical, they may be used to rotate the plane of polarization of light.  If the molecules are not asymmetrical, they may become so when the material is strained.

If the specimen is placed between crossed polarizers, virtually no light will get through an unstrained specimen.  Strains will show up as transparent regions, which are usually coloured.  Because light has wave structure, a graph of brightness against strain is not linear.  It oscillates.  If enough strain can be applied, coloured bands may be seen, indicating contours of equal strain.

 

By placing a piece of transparent material between crossed polarizers we can sometimes detect variations in thickness, variations in strain, variations in composition, or variations in orientation of crystal axes.  The picture below shows a perfectly good set-square, the function of which is not at all affected by the internal strains revealed by the polarised light.  In interpreting this type of picture we need to consider the possiblity that the colours maybe influenced by the thickness of the material.

Strains may be left in components after welding, rolling, injection moulding, extrusion, and other forming processes.

Here is a picture of a part of an adjustable set-square.  It does not produce any strong colours, but there are clearly indicated strains around the hole, though not much seems to be happening elsewhere, except at the two rivet holes.

This picture shows a CD box.  Three other boxes produced very similar pictures.  The reproduction process does not do justice to the colours, which have been subjected to tri-colour photography, scanning, JPEG, and display on a screen.  In any case, the complexity that can be hidden in a simple object is obvious.  These strains are quite large.  Adding stresses using a vice, a piece of ice, and a soldering iron made very little difference.

Here is another plastic box.  As it shows closer fringes we can conclude that the strains are higher than in the CD box.

The pictures below show a strip of perspex, with and without strain.and without strain.  The neutral axis is visible as a darker band in the second picture.

 

 

 

Aurora Borealis?

Warners.jpg (27733 bytes)Not an aurora, just the windscreen of a Peugeot 106, viewed between polarizers.

 

Returning to thermal expansion, it should be made clear that expansion is not in itself a problem.  If an isolated piece of metal gets uniformly hotter it expands, but experiences no internal stress.  But of course you cannot actually make something uniformly hotter, because you need a thermal gradient in order for the heat to flow into the object.

What you can do is to heat an object so slowly that the differential expansion is very small, and therefore does not create too much stress.

The cracking of thick glass is not caused by temperature: it is caused by temperature differences in the glass.

  

These cracks in the glaze of a pot are deliberate.  They are caused by differential contraction between pot and glaze.  Here are more examples.

JapanC3.jpg (124184 bytes)

 

Here is a pane of glass which has cracked.  The pattern resembles the stress field around a bar magnet or a pair of electric charges.  The glass is firmly held by the frame.  Perhaps the assembly has induced stresses in the frame and the glass.  Glass can absorb less energy per unit than most metals, and so breaks more easily.

As with so many other things that we humans define, if we look hard, we find that things are not as simple as we thought, and categories as not as clearly separated.  In any object, how can we know all the stresses?  For long thin struts and ties, we think of the stresses as being along the members, but in the page on attachments, we see that near the ends this is not the case.

Look at the left picture.  It shows a part of a large wall which has cracked from bottom to top.  The ground has moved, and the wall, though strong against compression, is feeble against tension and shear, and is rigid.  The solution to a problem is not always the obvious one.  The second picture shows a half-timbered building.  These are built with wooden frames, within which some other material, often brick, is inserted.  The bricks are not always laid horizontally, and even be at 45 degrees to the horizontal.  What happens in such a building is that the wooden parts, and especially the joints, are not as rigid as masonry, and can absorb energy.  Within the cells, the areas of brickwork are quite small, and are unlikely to crack.   

If we try to repair a piece of wooden furniture with a glue that is too rigid, we may stress it too much and cause further problems.  An important consideration in any structure is to get the right proportions of strength, rigidity and ability to absorb energy.  Many natural materials are able to absorb a lot of energy.  These include tendon, ligament, skin and leather.  At the other extreme we have glass, which is rigid and strong in compression, but breakable with little absorption of energy.

Here is another wall that has been distorted, this time by pressure from one side.  The pictures show a standard view, a vertically squashed view to show the curvature, and a belated attempt to prevent further distortion.  Old buildings quite commonly have plates on the outside, where long bars have been passed through to hold in the middle-age spread.

 

A bit of maths

The behaviour of mechanical parts has a parallel in mathematics.  If we imagine a long continuous parallel beam on a number of supports, we can see that if they are not level, there will be extra stresses in the beam.  The parallel in maths is that if we make a number of measurements, and we form the mean of the numbers, each individual measurement is seen to be slightly different from the mean.

All these differences correspond loosely to the induced stresses.  They arise because we have more measurements than are strictly needed to define the result.  Having too many measurements brings two benefits.  Firstly, a more accurate result is obtained, because random errors tend to cancel.  Secondly, by subtracting the mean from each measurement, we can find out the distribution and range of the errors.

This process can be extended to the case in which there are numerous unknown variables, and numerous equations relating the measurements.  If the number of equations is equal to the number of unknowns then we have just enough information.  But if there are too many equations, then no set of values will fit them all.  We have to find a set that gives the best fit.

For this we can use a simple least-squares fit, minimising the sum of the squares of the differences between the fitted values and the actual values.  Better still,  we can weight the value according to the expected measurement errors, which may not be the same for all the values.  As with the averages, the differences between measured and calculated values represent a "strain". 

In the case of a beam, the sum of the squares of the strains is related to the stored energy.

The diagram below shows a table of data that fall roughly on a straight line.  If we have reason to believe that that they represent linear behaviour, and that the deviations are purely caused by measuring error, we can calculate a best fit using the least squares method.  

The third column shows the differences between the data and the values generated by a linear formula.  The fourth column shows the squares of these differences.  The least squares method consists in changing the position and the slope of the black line until the sum of the squares is as small as possible.  If it is known that the measuring inaccuracy varies along the line, this can be taken into account in making the addition, by weighting the deviations according to the reciprocal of the inaccuracy.

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Answers to Questions

Truss with missing parts

AB missing – A B and C will move down.  AB gets shorter, so AB was in compression.  The structure might break at C as it falls.

DE missing – supports both hinged.  As the supports form a triangle with F, in theory the bridge could survive, if the supports can withstand the large outward thrust resulting from the implied flat triangle which has F as its apex.

DE missing – one support sliding.  D E and F can all fall, and DE will get bigger.  So part DE must have been in tension.

 

 

 

 

 

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